Python编程技巧：高效寻找100-1000范围内的最小5个素数及统计1000以内所有素数方法分享

python编程求100--1000范围内最小的5个素数。

n=0foriinrange(100,1000):x=[1ifi/d==int(i/d)else0fordinrange(2,int(i/2))]ifsum(x)==0:print(i)n=n+1ifn>5：休息

编写Python程序:输出1000以内所有的素数,每行10个,并统计个数？

您可以使用此Python程序将所有素数放入每行M、X内，并计算数字：0.5)+1):ifi%j==0:is_prime=Falsebreakifis_prime:prime(i,end='\t')count+=1ifcount==0:prim()prime('\n他们是第一个数字'.format(count))程序中使用了两个循环外循环2之间的所有数并枚举M，内循环判断当前数是否为素数。
如果当前数为第一个数，则输出该数，并将计数器加1；最后输出素数的个数。

求10-1000之间所有的素数Python

classPrime:res=[2,3,5,7,11,13,17,19,23,29,\31,37,41,43,47,53,59,61,67,\71,73,79,83,89,97,101,103,\107,109,113,127,131,137,\139,149,151,157,163,167,173,\179,181,191,193,197,199,211,\223,227,229,233,239,241,251,\257,263,269,271,277,281,283,\293,307,311,313,317,331,337,\347,349,353,359,367,373,379,\383,389,397,401,409,419,421,\431,433,439,443,449,457,461,\463,467,479,487,491,499,503,\509,521,523,541,547,557,563,\569,571,577,587,593,599,601,\607,613,617,619,631,641,643,\647,653,659,661,673,677,683,\691,701,709,719,727,733,739,\743,751,757,761,769,773,787,\797,809,811,821,823,827,829,\839,853,857,859,863,877,881,\883,887,907,911,919,929,937,\941,947,953,967,971,977,983,\991,997]defgetList(self):return.res.